Question

. What is the vertical asymptote(s) for y=x-5/x^2-4x-12​

Answer 1

x = -2 and 6

Explanation:

To find vertical asymptote, set the denominator equal to 0 and solve for x. See the guidelines below for determining VA

`y=(x-5)/(x^(2) -4x-12)`

`x^(2) -4x-12=0`

`x^(2) -6x+2x-12=0`

`x(x-6)+2(x-6)=0`

`(x+2)(x-6)=0`

`x=-2,6`

Hope this helps and God bless!