Question

- Calcular la magnitud de la fuerza eléctrica entre dos cargas cuyos valores son: q1 = 3.5 coulomb, q2 = 6 coulomb, al estar separadas en el vacío por una distancia de 0,4 m.

Answer 1

FE = 1.17*10^12 N

Step-by-step explanation:

The magnitude of the electric force is given by the following formula:

`F_E=k(q_1q_2)/(r^2)` ( 1 )

q1 = 3.5C

q2 = 6C

r = 0.4m

k: Coulomb's constant = 8.98*10^9 Nm^2/C^2

You replace the values of q1, q2, r and k in the expression (1):

`F_E=(8.98*10^9Nm^2/C^2)((3.5C)(6C))/((0.4m)^2)\\\\F_E=1.17*10^(12)N`

hence, the magnitude of the electric force is 1.17*10^12 N