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What is the center of the circle given by the equation (x−6)^2+(y+3)^2=7^2?

What is the center of the circle given by the equation (x−6)^2+(y+3)^2=7^2?
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2 votes
What is the center of the circle given by the equation (x−6)^2+(y+3)^2=7^2?

User Itwarilal
by
9.0k points

1 Answer

2 votes

Answer:

(6,-3)

Explanation:

online calculator

User Ed Manet
by
8.2k points
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