Question

A thermal insulating sleeve is used to cover the lateral surface of a hot water heater to help improve efficiency. The hot water tank is a cylinder with a 13 inch radius and a 75 inch height. The sleeve is 3 inches thick. The insulting material that makes up the sleeve is a fiberglass composite. How many cubic inches of fiberglass composite are needed to create each sleeve, to the nearest tenth of a cubic foot ?

Answer 1

706.85775

Explanation:

First you find the volume of the tank

13*3.14159=40.84067

40.84067*75=3063.05025

Then find the volume of both the tank and sleeve

13+3=16

16*3.14159=50.26544

50.26544*75=3769.908

Subtract the original volume with the combined volume

3769.908-3063.05025=706.85775