Question

For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 32 N acts on a certain object, the acceleration of the object is 4 m/s^2. If the acceleration of the object becomes 7 m/s^2, what is the force?

Answer 1

The new force acting on the object is 56 N.

Explanation:

The force acting on the object is given by the product of mass and its acceleration. Its mathematical form is given by :

`F=ma`

It means that force is acting on the object varies directly with the object's acceleration.

We have,

`F_1=32\ N\\\\a_1=4\ m/s^2\\\\a_2=7\ m/s^2`

F₂ is new force

So,

`(F_1)/(F_2)=(a_1)/(a_2)\\\\F_2=(F_1a_2)/(a_1)\\\\F_2=(32* 7)/(4)\\\\F_2=56\ N`

So, the new force acting on the object is 56 N.