Question

If an object is dropped from the height of 54 feet the function h=-16t2 +54 gives the height of the object after t seconds approximately how long will it take before the object hits the ground

Answer 1

t= +/-
`(3√(6))/(4)`

Explanation:

set h=0, 0=-16
`t^(2)`+54, add the -16
`t^(2)` to the other side, 16
`t^(2)`=54, divide the 16 off,
`t^(2)`=
`(54)/(16)`, square root both sides, t= +/-
`\sqrt[]{(54)/(16) }` , t= +/-
`√(54)`/4, t= +/-
`(3√(6))/(4)` , the object will hit the ground when t= +/-
`(3√(6))/(4)`