Question

A 1.35 kg block is pulled across a

flat, frictionless floor with a 3.07 N
force at 32.0° above horizontal.
What is the acceleration of the block?

Answer 1

1.93

Step-by-step explanation:

F= cos(angle) x N

F= cos(32)x 3.07 = 2.6035

F=ma

=>a= f/m

A=2.6035/1.35

A= 1.93

I know someone answered this already. This is for anyone who is confused and want the explanation for the answer. Have a great day!

Answer 2

1.93 m/s^2

Step-by-step explanation: