Question

.divide the problem.

Answer 1

`x - 2x - 15 \: divided \: by \: x - 3`

1. according to the above x²-2x-15 divided by the number below x-3 first I cancel out the x
2. 
   `x - 2x - 15 \: divided \: by \: - 3`
3. the we solve the next x-5 divided by x²-9 then as usual rule out the x
4. 
   `- 5 \: divided \: by \: x - 9`
5. now we only have x-2x-15 divided by-3 divided by-5÷x-9 now our next step is to again single the equations out
6. 
   `x - 2x - 15 \: divided \: by \: - 3 \: lets \: rue \\s \: rule \: out \: - 3 \: and \: 15 \: giving \: us \: x - 2x - 5`
7. now the next -5 divided by x-9 here there's nothing to rule out therefore the sign "÷" is changed to "×" cancel out the -5 and therefore we have
8. 
   `x - 2x = x - 9 \: as \: final \: answer`