Answer:
C: 1 over 7 to the 2nd power
Explanation:
The question is:
![7^(3) * 7^(-5)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ad8rwpb093kepfionszva0gieb7vz6q9p9.png)
When multiplying exponents, the base stays the same, while the power is added. In this question, the powers are 3 and -5.
![3+-5=-2](https://img.qammunity.org/2021/formulas/mathematics/high-school/27mroskofqu927t3bp5vnf0vbgj6qf7fjx.png)
The exponent will become:
![7^(-2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/fv1239pmc2pmn4fu9753sy0det5t9wr23o.png)
Since the power is negative, it is improper. The negative can be removed by moving the power down and making it a fraction over 1.
![7^(-2) \rightarrow (1)/(7^(2) )](https://img.qammunity.org/2021/formulas/mathematics/high-school/1jr6w00wrdqtsf1ht7hwb199y2jgo1ddat.png)
The answer is
, also written as "1 over 7 to the 2nd power".