1. For the first inequality, Luz can buy less than 5 computers (since
represents the number of computers and must be less than 5).
2. For the second set of inequalities,
must be greater than -6 and less than 0.
The image shows a mathematical problem with two inequalities:
1.
![\( 70x < 350 \)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/bxbyi2j27ly8qc1x25vtulpdz3q4zwoian.png)
2.
![\( x + 3 < 3 \) and \( x + 3 > -3 \)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/aty08cztk5x5pp824um4n8ry0z3vxugxmo.png)
To solve these inequalities step by step, we'll perform the following calculations:
For the first inequality:
![\[ 70x < 350 \]](https://img.qammunity.org/2021/formulas/mathematics/middle-school/vxpr19e7auu9gavldn484f5hawfv2oi5pe.png)
1. Divide both sides by 70 to solve for x:
![\[ x < (350)/(70) \]](https://img.qammunity.org/2021/formulas/mathematics/middle-school/jrcdbr1673ocqlzmrak8cm48y76da2aca2.png)
For the second set of inequalities:
![\[ x + 3 < 3 \] and \( x + 3 > -3 \)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/in23deyap2fpzfib71p96upustpq0mi0fi.png)
1. Subtract 3 from all parts of the compound inequality:
and
![\( x > -3 - 3 \)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/wtd1s8v3fnhdj3ue4ckq3qbxygpr2cxef8.png)
and
![\( x > -6 \)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/wxwwo9s9n79ev0b3oe39anzia9zf8dy032.png)
Now let's calculate the values.
Solution for the inequalities:
First inequality:
![\[ 70x < 350 \]](https://img.qammunity.org/2021/formulas/mathematics/middle-school/vxpr19e7auu9gavldn484f5hawfv2oi5pe.png)
After dividing both sides by 70, we get:
![\[ x < 5 \]](https://img.qammunity.org/2021/formulas/mathematics/middle-school/zeh204ssjpjooywe50fzgr55o59lcpi55z.png)
Second set of inequalities:
and
![\( x + 3 > -3 \)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/eupgc2zlaw2egjdv5rjlrlryk19cin36rn.png)
After subtracting 3 from all parts of the compound inequality, we get:
and
![\( x > -6 \)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/wxwwo9s9n79ev0b3oe39anzia9zf8dy032.png)
Thus, the solution to the inequalities are:
1. For the first inequality, Luz can buy less than 5 computers (since
represents the number of computers and must be less than 5).
2. For the second set of inequalities,
must be greater than -6 and less than 0.
If we interpret
as the number of items Luz can buy, the negative values don't make sense in a real-world context, as you cannot buy a negative number of items. Therefore, the practical solution for the second inequality is that Luz cannot buy any items since
must be less than 0 and whole numbers (non-negative integers) are required for the count of items.