Question

Which parabola will have a minimum value vertex? On a coordinate plane, a parabola opens down with x-intercepts at (negative 2.2, 0) and (2.2, 0), and a y-intercept at the vertex (0, 5). On a coordinate plane, a parabola opens down with a vertex at (0, 0). On a coordinate plane, a parabola opens down with x-intercepts at (negative 1, 0) and (2.3, 0), a y-intercept at (0, 2), and has a vertex at (0.75, 2.5). On a coordinate plane, a parabola opens up with x-intercepts at (negative 2, 0) and (2, 0), and a y-intercept at the vertex (0, negative 4).

Answer 1

yes, the correct answer is D

Explanation:

got it right in edg 2020

hope this is of help :)

Answer 2

(D)On a coordinate plane, a parabola opens up with x-intercepts at (negative 2, 0) and (2, 0), and a y-intercept at the vertex (0, negative 4).

Explanation:

For a parabola
`y=ax^2+bx+c` to have a minimum vertex, it must open upward. (a>0).

In the given options, the parabola which opens upward is option D.

On a coordinate plane, a parabola opens up with x-intercepts at (negative 2, 0) and (2, 0), and a y-intercept at the vertex (0, negative 4).

Therefore, it has a minimum vertex with coordinates (0,-4).