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Um motor que possui uma polia de 160 mm de diâmetro desenvolve 900 rpme move um eixo de transmissão cuja polia tem 300 mm de diâmetro. Calculea rotação do eixo. n1/n2=D2/D1 n1=900 n2=? D2=300 D1=160
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Um motor que possui uma polia de 160 mm de diâmetro desenvolve 900 rpme move um eixo de transmissão cuja polia tem 300 mm de diâmetro. Calculea rotação do eixo. n1/n2=D2/D1 n1=900 n2=? D2=300 D1=160

User Techmad
by
4.5k points

1 Answer

3 votes

Answer: 480rpm

Step-by-step explanation:

Given Data:

D1 = 160mm

D2 = 300mm

n1 = 900

n2 = ?

Therefore:

The axis of rotation

n1/n2 = D2/D1

= 900/n2 * 300/160

n2 = 900 * 160 / 300

n2 = 144,000 / 300

n2 = 480 rpm

User Susheel Singh
by
4.6k points
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