Question

How many atoms of Ca are in 4.7 moles of calcium?

Answer 1

Answer: There are
`28.303 * 10^(23)` atoms in 4.7 moles of calcium.

Step-by-step explanation:

According to Avogardo's number for every 1 mole of a substance there will be
`6.022 * 10^(23)` atoms.

For the given Ca atom there are 4.7 moles. Hence the number of atoms present in 4.7 moles will be calculated as follows.

Moles present =
`4.7 * 6.022 * 10^(23)` atoms

=
`28.303 * 10^(23)` atoms

Thus, we can conclude that there are
`28.303 * 10^(23)` atoms in 4.7 moles of calcium.