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What is the surface area of a pyramid with a base of a regular hexagon and a side length of 10 and a height of 16

1 Answer

7 votes

Answer:

A≈805.61

Explanation:


(3√(3) )/(2) a^(2) + 3a \sqrt[a]{h^(2) + (3a^2)/(4) }

That's the formula↑

User Mollerhoj
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