Question

Tim Worker is doing his budget. He discovers that the average miscellaneous expense is $45.00 with a standard deviation of $16.00. What percent of his expense in this category would he expect to fall between $38.60 and $57.80? The z for $38.60 = -___. The percent of area associated with $38.60 = ___%

The z for $57.80 =___ . The percent of area associated with $57.80 = ___%
Adding the two together, the percent of his expenses between $38.60 and $57.80 is ___%

Answer 1

Step-by-

1. {

The z for $38.60 = (38.60 - 45)/16 = -0.4

The percent of area associated with $38.60 = P(z < -0.4) = 0.34458 =34.46%

The z for $57.80 = (57.8 - 45)/16 = 0.8.

The percent of area associated with $57.80 = P(z < 0.8) = 0.78814 = 78.81%

the percent of his expenses between $38.60 and $57.80 is (78.81 - 34.46) = 44.35%

1. }

Explanation: Sorry for the late reply hope I helped.