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What is the remainder when x^3 - 1 is divided by (x+2)

User Xamox
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Answer:

The remainder is 9

Explanation:

Mikey, I'm going to find the answer to this problem using synthetic division.

x^3 - 1 needs to be written as 1x^3 + 0x2 - 0x - 1. Thus, the coefficients for x^3 - 1 are {1, 0, 0, -1}.

Division of x^3 - 1 by x + 2 requires that we use -2 as a possible root/solution. Setting up synthetic division, we get:

-2 / 1 0 0 -1

-2 4 -8

____________

1 -2 4 -9 The remainder is 9.

User TSL
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