Question

What mass of NaOH is contained in 2.5L

Of a 0.010M solution?
a 0.010g
B. 1.0g
c. 2.5g
D. 0.40g

Answer 1

B. 1.0g

Step-by-step explanation:

Step 1

The molarity of the solution is 0.010 M, that is, there are 0.010 moles of sodium hydroxide per liter of solution. The moles of NaOH in 2.5 L of solution are:

`2.5LSol * (0.010molNaOH)/(1LSol) =0.025molNaOH`

Step 2

The molar mass of sodium hydroxide is 40.00 g/mol. The mass corresponding to 0.025 moles is:

`0.025 mol * (40.00g)/(mol) =1.0 g`

There is 1.0 g of NaOH in the solution.