Question

On a coordinate plane, parallelogram A B C D has points (3, 6), (6, 5), (5, 1), and (2, 2).

What is the area of parallelogram ABCD?

Answer 1

Answer: The area is about 13.01.

Explanation:

so to do this we need to find the distance between these points.And we do that by using the Pythagorean rule a^2 + b^2=C^2

(3,6) and (6,5)

3^2 + 1^2 = c^2

c=
`√(10)`

(6,5) and (5,1)

1^2 + 4^2=
`√(17)`

`√(10) * √(17)`= 13.038