Answer:
Problem a ) Problem b )
r ⇒ 9 ft, r ⇒ 1.5 m,
Base Area ⇒ ( About ) 254.3 ft^2, Base Area ⇒ ( About ) 7.1 m^2,
Volume ⇒ ( About ) 1526 ft^3 Volume ⇒ ( About ) 21.2 m^3
Explanation:
Problem a )
~ Provided that r ⇒ radius... ~
1. The Base of this cylinderical object is, of course, a circle. Knowing that, the Base area of the cylinder can be computed through πr^2, and with the r ⇒ 9 ft, Base Area ⇒ π ( 9 )^2 ⇒ 81π ⇒ 254.34 ft^2.
2. With the Base Area being 254.34 we can calculate the Volume through the basic formula Base * height, and with the height being 6 ft:
Volume ⇒ ( 254.34 ) * ( 6 ) ⇒ 1526.04 ft^3.
Problem b )
~ Provided that r ⇒ radius... ~
1. The Base of this cylinderical object is, of course, a circle. Knowing that, the Base area of the cylinder can be computed through πr^2, with diameter ⇒ 3 m we know that r ⇒ 3/2 = 1.5 m. That being said, Base Area is thus ⇒ π ( 1.5 )^2 ⇒ 2.25π ⇒ 7.065 m^2.
2. With the Base Area being 7.065, we can calculate the Volume through the basic formula Base * height, and with the height being 3 m:
Volume ⇒ ( 7.065 ) * ( 3 ) ⇒ 21.195 m^3.