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Easy Volume Problems.

Easy Volume Problems.-example-1
User Raya
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Answer:

Problem a ) Problem b )

r ⇒ 4 cm, r ⇒ 7 ft,

Base Area ⇒ ( About ) 50.2 cm^2, Base Area ⇒ ( About )153.9 ft^2,

Volume ⇒ ( About ) 803.8 cm^3 Volume ⇒ ( About ) 769.3 ft^3

Explanation:

Problem a )

~ Provided that r ⇒ radius... ~

1. The Base of this cylinderical object is, of course, a circle. Knowing that, the Base area of the cylinder can be computed through πr^2, and with the diameter as 8 cm, r ⇒ 8/2 = 4 cm. Now we know that r ⇒ 4 cm, and that Base Area ⇒ π ( 4 )^2 ⇒ 16π ⇒ 50.24 cm^2.

2. With the Base Area being 50.24, we can calculate the Volume through the basic formula Base * height, and with the height being 16 cm:

Volume ⇒ ( 50.24 ) * ( 16 ) ⇒ 803.84 cm^3.

Problem b )

~ Provided that r ⇒ radius... ~

1. The Base of this cylinderical object is, of course, a circle. Knowing that, the Base area of the cylinder can be computed through πr^2, and with r ⇒ 7 ft we know that the Base Area ⇒ π ( 7 )^2 ⇒ 49π ⇒ 153.86 ft^2.

2. With the Base Area being 153.96, we can calculate the Volume through the basic formula Base * height, and with the height being 5 ft:

Volume ⇒ ( 153.86 ) * ( 5 ) ⇒ 769.3 ft^3.

User Ther
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