Question

What is the area of a circle with the equation (x - 3)^2 + (y + 2)^2 = 64

Answer 1

200.96 square units

Explanation:

`(x - 3)^2 + (y + 2)^2 = 64\\(x - 3)^2 + (y + 2)^2 = 8^(2) \\equating \:it\: with\\(x - h)^2 + (y -k)^2 = r^(2)\\we\:find;\\r^(2) =8^(2)\\\therefore radius\: (r) = 8 units\\Area\: of\: circle\\=\pi r^(2) \\=3.14*8^2\\=3.14* 64\\=200.96 \:units^(2)`