Question

1. Write (x^2) + 3x – 1 in the form ((x + a)^2) + b​

Answer 1

`(x+(3)/(2))^(2)-(13)/(4)`

Explanation:

(x^2) + 3x – 1 = x² + 2×(3/2)x - 1

= [(x + 3/2)² - (3/2)²] - 1

= (x + 3/2)² - 9/4 - 1

= (x + 3/2)² - (9/4 + 4/4)

= (x + 3/2)² - 13/4