Answer:
The volume of water displaced by the ball is 1.156 m³
Step-by-step explanation:
Given;
mass of the object, m = 1156 g = 1.156 kg
density of the object, ρ' = 6.00 × kg/m³
density of the fluid (water) ρ = 1.0 × kg/m³
From Archimedes law, which states that the buoyant force on an object is equal to the weight of the fluid displaced by the object.
Buoyant force is given as;
Fb = ρVg = mg
Where;
Fb is the buoyant force
ρ is the density the fluid
V is the submerged volume
g is the acceleration due to gravity
m is mass of the object
The equation above can be reduced to;
ρV = m
V = m/ρ
V = 1.156/1
V = 1.156 m³
Thus, volume of the object (ball) submerged is equal to volume of the fluid (water) displaced = 1.156 m³