Question

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How many molecules are in 25.4 grams of dinitrogen pentoxide, N2O5?

Answer 1

Answer: There are
`1.415* 10^(23)` molecules in 25.4 g of
`N_2O_5`

Step-by-step explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number
`6.023* 10^(23)` of particles.

To calculate the moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=(25.4g)/(108g/mol)=0.235moles`

1 mole of
`N_2O_5` contains =
`6.023* 10^(23)` molecules

Thus 0.235 moles of
`N_2O_5` contains =
`(6.023* 10^(23))/(1)* 0.235=1.415* 10^(23)` molecules.

There are
`1.415* 10^(23)` molecules in 25.4 g of
`N_2O_5`