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Determine between which consecutive integers the real zeros of f(x) = 2x - 5x+1 are located.

between 0&1 and 1&2
between 0&1 and 2&3
b. between -1&0 and 2&3
d. between 1&2 and 2&3
a
C.
Please select the best answer from the choices provided
OA
OB
OC
OD

User Manny D
by
8.8k points

1 Answer

5 votes

Answer:

between 0&1 and 2&3

Explanation:

(Assuming that f(x) = 2x^2 - 5x + 1)

To solve this question we just need to find the zeros of the function f(x), and we do that by making f(x) = 0 and finding the values of x:

2x^2 - 5x + 1 = 0

Now we can use Bhaskara's formula:

Delta = b^2 - 4ac = 25 - 4*2 = 17

sqrt(Delta) = 4.12

x1 = (5 + 4.12) / 4 = 2.28

x2 = (5 - 4.12) / 4 = 0.22

the zero x1 = 2.28 is between 2 and 3, and the zero x2 = 0.22 is between 0 and 1, so the answer is 'between 0&1 and 2&3'

As the options A, B, C and D are not clear in the question text, you can just mark the option that has this result.

User Micha Wiedenmann
by
8.5k points
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