Question

Determine the percentage composition (by mass) of oxygen in NH4NO3.

Answer 1

60%

Step-by-step explanation:

M(NH4NO3) = 2*14 +4*1 +3*16 = 80 g/mol

M(3O) = 3*16 = 48 g/mol

(48/80) *100 % =60% oxygen by mass.