Question

Helium in a 100 L container at a pressure of 65.6 atm and temperature of 250 K is transferred to a container with a volume of 250 L and a temperature of 300 K. What is the new pressure?

Answer 1

P2 = 31.5atm

Step-by-step explanation:

V1 = 100L

P1 = 65.6atm

T1 = 250K

V2 = 250L

T2 = 300K

P2 = ?

To find P2, we have to use combined gas equation, which is the combination of Boyle's law, Charles law and pressure law

(P1 × V1) / T1 = (P2 × V2) / T2

P1 × V1 × T2 = P2 × V2 × T1

P2 = (P1 × V1 × T2) / V2 × T1

P2 = (65.6 × 100 × 300) / (250 × 250)

P2 = 1968000 / 62500

P2 = 31.488atm

P2 = 31.5atm

The final pressure of the gas is approximately 31.5atm