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The cost of a daily newspaper varies from city to city. However, the variation among prices remains steady with a population standard deviation of $0.20. A study was done to test the claim that the mean cost of a daily newspaper is $1.00. Twelve costs yield a mean cost of $0.93 with a standard deviation of $0.18. Do the data support the claim at the 1% level?

User Saboora
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1 Answer

4 votes

Answer:

Yes, there is sufficient evidence to support the claim that the mean cost is $1.

Explanation:

Data Given:

The population standard deviation
\sigma = $0.2

The sample mean cost
\bar {X} = $0.93

The sample size n = 12

From above we can use the Z-test for testing the mean from the above given data.

To check whether the mean cost of newspaper is $1.00


\mathbf{H_o} :
\mu = $1


\mathbf{H_1} :
\mu
\\eq $1

The test statistics Z =
\frac{\bar {X}- \mu}{(\sigma )/(√(n)) }

Z =
(0.93- 1)/((0.2)/(√(12)) )

Z = -1.212

The P-value = 2P (Z< - 1.212)

= 2 × 0.1128

= 0.2256

Since the value of P is more than the significance level; do not reject the
\mathbf{H_o}

Conclusion: We therefore conclude that there is sufficient evidence to support the claim that the mean cost is $1.

User Johnluetke
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