1 Answer

Alexander Fedotov · Answer 1 · 2021-11-21T05:05:45+0000

Answer:

(x-3) ^2 +(y-4) ^2 =4

Explanation:

Center of circle:

$C=(3,\:4) =(h, \:k) \\$

$Radius \: r = 2$

Equation of circle in standard form is:

(x-h) ^2 +(y-k) ^2 =r^2

Substituting the values of h, k and r in above equation, we find:

$(x-3) ^2 +(y-4) ^2 =2^2\\</p><p> \purple {\boxed {\bold {(x-3) ^2 +(y-4) ^2 =4}}} \\</p><p>$

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