Question

Consider the nuclear equation below. 235/92 U right arrow superscript 4 subscript 2 upper H e. What is the nuclide symbol of X? Superscript 231 subscript 94 upper P u. Superscript 235 subscript 90 upper T h. Superscript 239 subscript 94 upper P u. Superscript 231 subscript 90 upper T h.

Answer 1

c

Step-by-step explanation:

cuz yea

Answer 2

`^(239)_(97)Pu`

Step-by-step explanation:

The capture of an alpha particle (
`^(4)_(2)He`) by the
`^(235)_(92)U` is:

`^(235)_(95)U + ^(4)_(2)He \rightarrow X`

The capture of an alpha particle by the uranium produces an increase in the atomic number of the uranium in four (because of the two protons and two neutrons of the alpha particle) and an increase of the protons number in two.

Therefore, the nuclide is:

`^(235)_(95)U + ^(4)_(2)He \rightarrow ^(239)_(97)Pu`

Hence, the correct option is the third option:
`^(239)_(97)Pu`

I hope it helps you!