Question

What must be the volume of a balloon that can hold 313.0 g of helium gas and ascend from sea level to an altitude, where the temperature is 10.00C and the pressure is 635.4 mmHg?

Answer 1

Answer: The volume of a balloon that can hold 313.0 g of helium gas is 2174 L

Step-by-step explanation:

According to ideal gas equation:

`PV=nRT`

P = pressure of gas = 635.4 mmHg = 0.8360 atm (760mmHg=1 atm)

V = Volume of gas = ?

n = number of moles =
`\frac{\text {given mass}}{\text {Molar mass}}=(313.0g)/(4g/mol)=78.25mol`

R = gas constant =
`0.0821Latm/Kmol`

T =temperature =
`10.00^0C=(10.00+273)K=283.00K`

`V=(nRT)/(P)`

`V=(78.25mol* 0.0820 Latm/K mol* 283.00K)/(0.8360atm)=2174L`

Thus volume of a balloon that can hold 313.0 g of helium gas is 2174 L