Answer:
![Zn^0\rightarrow Zn^(+2)+2e^-](https://img.qammunity.org/2021/formulas/chemistry/middle-school/8gsq8h9wau8de8s1r5kqwumtosxd15frib.png)
Step-by-step explanation:
Hello,
In this case, the described chemical reaction is:
![Zn(s)+HCl(aq)\rightarrow ZnCl_2(aq)+H_2(g)](https://img.qammunity.org/2021/formulas/chemistry/middle-school/cp4kem3nfh8rgienjc836lbv2lv2j7ww7q.png)
Then, to identify the half reactions we must assign the oxidation state for each element as shown below:
![Zn^0(s)+H^+Cl^-(aq)\rightarrow Zn^(+2)Cl_2^-(aq)+H_2^0(g)](https://img.qammunity.org/2021/formulas/chemistry/middle-school/icoklbufy846hb77miznymwe8ab5j0i9a5.png)
In such a way, we can notice zinc's oxidation state changes from 0 to +2, therefore, it is the oxidizes species for which the half reaction which correctly describes the oxidation that is taking place is:
![Zn^0\rightarrow Zn^(+2)+2e^-](https://img.qammunity.org/2021/formulas/chemistry/middle-school/8gsq8h9wau8de8s1r5kqwumtosxd15frib.png)
Best regards.