Question

D: Application ( /10)

The world's largest pendulum clock has a period of 2.00 seconds with a maximum amplitude of
0.345 m to either side of the equilibrium position (EQ). [4]
a. Find a possible equation for the displacement of the spring from EQ at t seconds.​

Answer 1

The displacement equation for this periodic motion is given as

y = (0.345 Sin πt) m

y = (0.345 Sin 3.142t) m

Explanation:

The displacement equation for periodic motion is given as

y = A sin wt

A = amplitude of the motion, that is, the maximum displacement from the equilibrium position = 0.345 m

w = angular frequency = (2π/T)

T = period of the periodic motion = 2.00 s

w = (2π/T) = (2π/2) = π rad/s

t = time of motion, measured in seconds.

y = (0.345 Sin πt) m

y = (0.345 Sin 3.142t) m

Hope this Helps!!!