Question

The reaction A + 2B ® products has been found to have the rate law, rate = k[A] [B]2. While holding the concentration of A constant, the concentration of B is increased from x to 3x. Predict by what factor the rate of reaction increases.

Answer 1

The rate of the reaction will increase by a factor of 9.

Step-by-step explanation:

Hello,

In this case, considering the given second-order reaction, whose rate law results:

`r=k[A] [B]^2`

We easily infer that at constant concentration of A but tripling the concentration of B, we are going to obtain the following increasing factor while holding the remaining variables constant:

`Increase\ factor=(r_(final))/(r_(initial)) =(k[A][3*B]^2)/(k[A][B]^2) =(3^2)/(1) \\Increase\ factor=9`

Best regards.