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How many moles of koh are needed to neutralize 0.4 moles of hno3

User Pravin Raj
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2 Answers

3 votes

Answer:

0.4 moles of KOH

Step-by-step explanation:

Hello,

In this case, due to the chemical reaction:


KOH+HNO_3\rightarrow KNO_3+H_2O

Since 0.4 moles of nitric acid are reacting, and it is in a 1:1 molar ratio with potassium hydroxide, also 0.4 moles of KOH will be needed to neutralize the 0.4 moles of nitric acid.

Best regards.

User DavidN
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7.5k points
3 votes

Answer:

0.4 moles of KOH is required to neutralize 0.4 moles of HNO3.

Step-by-step explanation:

The equation of the reaction is

KOH(aq) + HNO3(aq) ------> KNO3(aq) + H2O(l)

This is a neutralization reaction. A neutralization reaction is a reaction between an acid and a base to form salt and water only.

Having written the balanced chemical reaction equation, we can now solve the prob!em stoichiometrically.

From the balanced reaction equation;

1 mole of KOH is required to neutralize 1 mole of HNO3

Therefore x moles of KOH is required to neutralize 0.4 moles of HNO3

x= 1×0.4/1 = 0.4 moles

Therefore, 0.4 moles of KOH is required to neutralize 0.4 moles of HNO3.

User IMParasharG
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