Question

What is the diameter of the smallest circle that would enclose 2,000 pennies?

Recall your model's equation: y=1.11x^{2}

Answer 1

Answer: 84.9

Explanation:

Model's equation: y=1.11x^2

Since y = 2000

y = 1.11x^2

2000 = 1.11x^2

x^2 = 2000/1.11

x^2 = 1801.8

x = 42.45

Diameter of the smallest circle will be:

= 2x

= 2 × 42.45

= 84.9