Answer:
A) A = X^2 + 11X + 24
B) X = 18 ft
C) 414 ft^2
D) 132 ft^2
Explanation:
A) Width W of yard and path = X + 3
Lenght L of path = X + 5 + 3 = X + 8 ft, therefore,
Area of yard and path = L x W = (X +3) x (X +8)
A = X^2 + 11X + 24
B) if area of the yard and path is 546 ft^2,
546 = X^2 + 11X + 24
X^2 +115X - 522 = 0 (quadratic equation)
Solving the quadratic equation gives
X = 18 and X = -29
Our answer can only be positive so we choose X = 18 ft
C) lenght of yard = 5 + 18 = 23 ft
Width = 18 ft
Therefore area = L x W = 23 x 18 = 414 ft^2
D) area of path = area of path and yard minus area of yard
= 546 - 414 = 132 ft^2