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01:59:13

Stan ran 4 To miles, which was 1 To fewer miles than Matt ran. Four students wrote and solved equations to find m, the

number of miles that Matt ran. Which student wrote and solved the equation correctly?

Molly's work

m+1-476

Emma's work

m-10-470

Alysa's work

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2 Answers

3 votes

Answer:

my bad dude i was tryna rate ur thing a 5 star

Explanation:

but accidentally hit the 1 star so sorry and u have the correct question thing and imma choose molly work!

User Andrew Romanov
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4.5k points
1 vote

Correct Question:

Stan ran
4(7)/(10) miles, which was
1(3)/(10) fewer miles than Matt ran. Four students wrote and solved equations to find m, the number of miles that Matt ran. Which student wrote and solved the equation correctly?

Molly’s work:


M + 1(3)/(10) = 4(7)/(10); M = 5(10)/(10) = 6.

Emma’s work:


M - 1(3)/(10) = 4(7)/(10); M = 3(10)/(10) = 4

Alysa’s work:


M + 1(3)/(10) = 4(7)/(10); M = 3(4)/(10) = 3 and two-fifths

Maddie’s work:


M - 1(3)/(10) = 4(7)/(10); M = 5(10)/(10) = 6

Answer:

Molly's Work is correct


M + 1(3)/(10) = 4(7)/(10); M = 5(10)/(10) = 6.

Explanation:

Let S represent distance covered by Stan and M represent the distance covered by Matt;

Given that the distance covered by Stan is
4(7)/(10) miles and it is
1(3)/(10) miles less than that covered by Matt;

This can be represented mathematically as


S = M - 1(3)/(10)

By substituting
4(7)/(10) for S;

This gives


4(7)/(10) = M - 1(3)/(10)

By collecting like terms


4(7)/(10) = M - 1(3)/(10) becomes


4(7)/(10) + 1(3)/(10) = M

Reorder


M = 4(7)/(10) + 1(3)/(10) ---- This is the correct equation

Solving further to get the distance covered by Matt;

Split fraction


M = 4 + (7)/(10) + 1 + (3)/(10)

Collect like terms


M = 4 + 1 + (7)/(10) + (3)/(10)


M = 5 + (7)/(10) + (3)/(10)

Add fraction (Take LCM)


M = 5 + (7 + 3)/(10)


M = 5 + (10)/(10)

Divide Fraction


M = 5 + 1


M = 6

Hence, the equation of the system is


M = 4(7)/(10) + 1(3)/(10)

and the solution is
M = 6

Molly’s work is correct

User Fusion
by
4.8k points