Question

A skier starting from rest accelerates in a straight line down a 43,000 m slope at 1 m/s. How fast were they moving after 5 s?

Answer 1

5m/s

Step-by-step explanation:

The skier accelerates at 1 m/s, then, the acceleration is:

`a=1(m)/(s^2)`

to find the speed after 5 seconds you use the following formula:

`a=(v-v_o)/(t)`

but vo = 0m/s because the skier is at rest at the beginning.

You do v the subject of the formula:

`v=at=(1(m)/(s^2))(5s)=5(m)/(s)`

hence, the velocity is 5m/s