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What is the molarity of 5.74 liters of solution made with 246 grams of iron (III) chloride (FeCl3)? Answer with 3 SDs.

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Answer:

0.264 mol/L

Step-by-step explanation:

Data obtained from the question includes:

Volume = 5.74L

Mass of FeCl3 = 246 g

Molarity =?

Next, we shall determine the number of mole in 246g of FeCl3.

This is illustrated below:

Mass of FeCl3 = 246g

Molar mass of FeCl3 = 56 + (35.5x3) = 162.5g/mol

Number of mole of FeCl3 =..?

Mole = Mass /Molar Mass

Number of mole of FeCl3 = 246/162.5

Number of mole of FeCl3 = 1.514 mol

Now, we can obtain the molarity of the solution as follow:

Molarity = mole /Volume

Volume = 5.74L

Mole of FeCl3 = 1.514 mol

Molarity = 1.514/5.74

Molarity = 0.264 mol/L

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