Explanation:
![Circumference = 2r\pi \\Area = r^2\pi](https://img.qammunity.org/2021/formulas/mathematics/high-school/proy6v4tjaf8ud9stqs0o93hv9gxidco6j.png)
In order for us to find the circumference, we need to find the radius from the given area by rearranging the area formula.
![r=\sqrt{(A)/(\pi ) }](https://img.qammunity.org/2021/formulas/mathematics/high-school/6xsqfdy7mbjgn2qkaae826egwzri8qbgc3.png)
![r=\sqrt{(113.1)/(\pi ) }](https://img.qammunity.org/2021/formulas/mathematics/high-school/7e6sszj8hlym0xywsiq4dnvuyaj9ifxzex.png)
![r=√(36)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/is6n4u72ibl6ui98h5d99vq333oz4dcfua.png)
![r=6](https://img.qammunity.org/2021/formulas/mathematics/college/b58axp9prslfs3w3b5xjmro5qk922f6lb2.png)
Now that we have the radius, we can find the circumference.
![Circumference=2(6)\pi](https://img.qammunity.org/2021/formulas/mathematics/high-school/2r09fy06xiglczo9aj8xpz1x34boyiiffb.png)
![Circumference=12\pi](https://img.qammunity.org/2021/formulas/mathematics/high-school/6ub4fmcwhlbsb5l0jhfaodgq2km1g0ufef.png)
![Circumference=37.68](https://img.qammunity.org/2021/formulas/mathematics/high-school/5txx34vybw6x6iwrav1rq29p4hulejm1f9.png)
So, when given 113.1 in sq for the area, the circumference of the circle is 37.68 in.