Answer:
Fig .A=>L=169.6 cm² and S= 226.2 cm²
Fig B=>L=31.4in² and S=70.7in²
Explanation:
See attachment for the figure
For figure A:
Given:
Radius 'r'= 3cm and height 'h'=9cm
->Lateral area formula is given by:
L = 2πrh => 2π(3)(9)
L= 54π cm² ≈169.6 cm²
-> next is to find surface area 'S'
S= L + 2πr² =>= 54π + 2π(3)²
S= 72π cm²≈ 226.2 cm²
Therefore,
The amount of paper needed for the label is the lateral area, 169.6 cm²
The amount of aluminum needed for the can is the surface area, 226.2 cm²
For figure B:
Given:
Radius 'r'= 2.5in and height 'h'=2in
->Lateral area formula is given by:
L = 2πrh => 2π(2.5)(2)
L= 10π in² ≈31.4in²
-> next is to find surface area 'S'
S= L + 2πr² =>= 10π + 2π(2.5)²
S= 22.5π in²≈ 70.7in²
The amount of paper needed for the label is the lateral area, 31.4in²
The amount of aluminum needed for the can is the surface area,70.7in²