Question

Point B has coordinates ​(3​,2​). The​ x-coordinate of point A is negative 3. The distance between point A and point B is 10 units. What are the possible coordinates of point​ A?

The possible coordinates of point A are

Answer 1

Either A= (-3,10)

OR A= (-3,-6)

Explanation:

A = (-3,y) B = ​(3​,2​)

(Distance from A to B) = √[(-3-3)²+(y-2)²]=10

√[36+y²-4y+4]=10

√[y²-4y+40]=10

squaring on both sides

y²-4y+40=100

y²-4y-60=0

y²-10y+6y-60=0

y(y-10) + 6 (y-10)=0

(y - 10)(y + 6)=0

Either y=10 =>A= (-3,10)

OR y=-6 =>A= (-3,-6)