Answer: The volume of 0.235 M
needed to titrate 40.0 mL of 0.0500 M
is 8.51 ml
Step-by-step explanation:
To calculate the volume of acid, we use the equation given by neutralization reaction:

where,
are the n-factor, molarity and volume of acid which is

are the n-factor, molarity and volume of base which is

We are given:

Putting values in above equation, we get:

Thus volume of 0.235 M
needed to titrate 40.0 mL of 0.0500 M
is 8.51 ml