Answer:
A normal distribution with a mean of 500 and a standard deviation of 100.
To find the probability that a randomly-selected score higher than 600 (P>600), we first find the z-score.
z = (value - mean)/SD = (600 - 500)/100 = 1
Check the table of z-score cumulative normal distribution, we found:
P(z<1) = 0.84134
=> P(> 600) = 1 -0.84134 = 0.15866 = ~16%
Hope this helps!
:)