Question

Solve 2sin^2x=sinx, if 0

Answer 1

Answer: D. 0, pi/6, pi, 5pi/6, and 2pi

Step-by-step explanation:

Refer to screenshot of Desmos graph below

Question: What are all the exact solutions of
`2sin^2x-sinx=0` for
`0\leq x\leq 2\pi`?

Answer 2

Step-by-step explanation:
sin
x
(
2
sin
x
+
1
)
=
0

Use trig table and unit circle -->
a. sin x = 0 => x = 0, and
x
=
π
and
x
=
2
π
b. 2sin x + 1 = 0 =>
sin
x
=
−
1
2
=>
x
=
7
π
6
and
x
=
11
π
6
.
Finally, within interval
[
0
,
2
π
]
,
there are 5 answers:
0
,
π
,
2
π
,
7
π
6
and
11
π
6