Answer:
cost of pass = $10.5
cost of souvenir = $7
cost of burger = $1.75
Explanation:
Total money with Danny = $23.75
Let the cost of pass be $x
As the souvenir cost 2/3 the cost of the pass
Thus cost of souvenir = $(2/3)x
Cost of burger is 1/4 of souvenir
Thus cost of burger = (1/4)*(2/3)x =$ 1/6x
Total cost of all the three item in terms of x
x + (2/3)x + ( 1/6)x
=>(6x+4x+x)/6 = 11x/6
Given that after money spent on buying all the three thing he has left $4.50
subtracting money spent on buying three things from total money is equal to $4.50
Mathematically it can be written as
$23.75 - 11x/6 = $4.50
=> $23.75 - $4.50= 11x/6
=>$19.25 = 11x/6
=> $19.25*6 = 11 x
=> $115.5 = 11x
=> $115.5/11 = x
=> x = 10.5
Thus,
cost of pass = x = $10.5
cost of souvenir = $(2/3)x =$(2/3)*10.5 = $7
cost of burger = $ 1/6x = $ (1/6)*10.5 = $1.75