Answer:
(a) Ff = 3.95N
(b) Ff = 5N
Step-by-step explanation:
(a) To find the friction force you use the second Newton law:
![F=ma](https://img.qammunity.org/2021/formulas/physics/college/kxqi3lxi3fjfv761qhdu0s1p00agxd9vve.png)
But you take into account the applied force and the opposite friction force:
![F_a-F_f=ma](https://img.qammunity.org/2021/formulas/physics/college/2ndd6v1enpgke589sh0ik84h2xeei7t7p7.png)
you do Ff the subject of the formula and replace the values of the parameters:
![F_f=F_a-ma=5N-(0.700kg)(1.5m/s^2)\\\\F_f=3.95N](https://img.qammunity.org/2021/formulas/physics/college/nst42n63qekx42i4qineos7h2fqjzrqvzh.png)
(b) In the case of a motion with constant velocity you have that there is no acceleration. Hence:
![F_a-F_f=0\\\\F_f=F_a\\\\F_f=5N](https://img.qammunity.org/2021/formulas/physics/college/n6qfewo8nyam8m3spquclkp3z4o5j1xic7.png)