Answer:
D) four times as great
Step-by-step explanation:
The current through a circuit or device is given by the formula:
I = q/t
q = (I)(t)
where,
I = current
q = charge
t = time
FOR AAA CELL:
I = 750 mA = 0.75 A
t = 5 min = (5)(60) sec = 300 sec
q = q₁
Therefore,
q₁ = (0.75 A)(300 sec)
q₁ = 225 Coulomb
FOR C CELL:
I = 750 mA = 0.75 A
t = 20 min = (20)(60) sec = 1200 sec
q = q₂
Therefore,
q₂ = (0.75 A)(1200 sec)
q₂ = 900 Coulomb
Thus, from the values of charges for both cells, it is clear that, Compared to the total charge transferred by the AAA cell through the bulb, the total charge transferred by the C cell through the bulb is:
D) four times as great