Answer:
26.18 m/s
Step-by-step explanation:
From the question,
The Energy stored in the string = kinetic energy of the arrow.
1/2(ke²) = 1/2(mv²)................. Equation 1
Where k = spring constant of the bowstring, e = extension, m = mass of the arrow, v = velocity of the arrow.
make v the subject of the equation
v = √(ke²/m).............. Equation 2
Given: k = 1175 N/m, e = 27 cm = 0.27 m, m = 125 g = 0.125 kg.
Substitute this values into equation 2
v = √(1175×0.27²/0.125)
v = √(685.26)
v = 26.18 m/s